The product of two consecutive odd integers is 99. if
x
is the smallest of the integers, write an equation in terms of
x
that describes the situation, and then find all such pairs of integers.

The equation in terms of x is x(x + 2) = 99 or

The pairs of integers are  -11 and -9 or 9 and 11

Solution:

Let the two consecutive odd integers be x and x + 2

Let "x" be the smallest integer

Given that product of two consecutive odd integers is 99

To find: an equation in terms of  x

Product of x and x + 2 = 99

Thus the equation in terms of x is found

Let us solve the above equation to find all pairs of integers

Solve the quadratic equation by grouping method

Middle term 2x can be written as 11x - 9x

Now group the terms,

Take "x" as common term from first group and 9 as common term from second group

Now take x + 11 as common term,

Equating to zero we get,

x + 11 = 0 or x - 9 = 0

x = -11 or x = 9

When x = -11 :

x + 2 = -11 + 2 = -9

Thus first set of two consecutive odd integers are -11 and -9

When x = 9 :

x + 2 = 9 + 2 = 11

Thus second set of two consecutive odd integers are 9 and 11

i believe a. 12x≥120 is the answer

first, let's see what the pattern is.

58 - x = 47

46 - x = 36

x = 9

so this means that the term after 25 is 25 - 9:

the next term in the sequence is 16.