One painting is sold for 5 times the amount of a second, the third was sold for $1500. if the total sale was for $13500, how much did the most expensive painting cost?

the most expensive painting is $10000

Step-by-step explanation:

Let x represent the amount for which the first painting was sold. One painting is sold for 5 times the amount of a second. This means that

x = 5y

The third was sold for $1500. If the total sale was for $13500, it means that

5y + y + 1500 = 13500

6y + 1500 = 13500

6y = 13500 - 1500 = 12000

y = 12000/6 = 2000

x = 5y = 5× 2000 = 10000

answer:

step-by-step explanation:

here, the total dishes = 10

dishes having meat = 3 ( chicken, meatloaf and hamburger )

thus, the probability of having meat on the chosen dishes = number of dishes having meat / total dishes

=

therefore, the probability of not having meat = 1- the probability of having meat on the chosen dishes

=

=

=

⇒ option b is correct.