3. if x +4, 2x+5, and 4x +3 represent the first three terms of an arithmetic sequence, then find the
value of x. what is the fourth term?

The value of x is 3 and the fourth term of an A.P is 19.

We have : first term = x+4

Second term =2x+5

Third term = 4x +3

second term =first term + common difference

Now, we know if the numbers are in A.P then the common difference is same.

So,

2x+5-(x+4) = 4x+3-(2x+5)

 2x+5-(x+4) = 2x-2

x+1 = 2x-2

 x=3

Therefore,

First term = 3+4=7

Second term =2(3)+5=11

Third term = 4(3) +3=15

Fourth term = 15 +4=19  

So, the fourth term is 19

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first term = initial number

second term = initial number + common difference

third term = initial number + 2(common difference)

So...

2x+5-(x+4) = common difference

4x+3-(2x+5) = also common difference

2x+5-(x+4) = x+1

4x+3-(2x+5) = 2x-2

Because x+1=2x-2 we can solve for x.

x=3

So the sequence goes... 7,11,15...

19 is the fourth term

the 8 in 8,420 is in the thousands place so it's value is 8 thousand.

the 8 in 6,870 is in the hundreds place so it's value is 8 hundred.

divide 8000 by 800 to find the answer:

8000 / 800 = 10

the 8 in 8,420 is 10 times greater than the 8 in 6,870

step-by-step explanation: