The circle with a center (10,1) and the radius 5 has equation

Explanation:

The general template of a circle is

(x-h)^2 + (y-k)^2 = r^2

Where,

We are given (10,1) as the center so (h,k) = (10,1) meaning that h = 10 and k = 1 pair up together.

r = 5 is the given radius.

Plug the values h = 10, k = 1, r = 5 into the equation to get:

(x-h)^2 + (y-k)^2 = r^2

(x-10)^2 + (y-1)^2 = 5^2

(x-10)^2 + (y-1)^2 = 25

-7/8

step-by-step explanation:

instead of subtracting you add the -6/8 and -1/8