Me i am on a test

which equation in slope-intercept form represents a line that is parallel to y=12x−2 and passes through the point (−8,1)?
y=12x−9
y=−2x−5
y=12x+5
y=−12x+5
y=−2x−7

The equation in slope-intercept form represents a line that is parallel to y = 12x − 2 and passes through the point (−8,1) is y = 12x + 97

Solution:

Given that we have to write the equation in slope intercept form for line that is parallel to y = 12x − 2 and passes through the point (−8, 1)

The slope intercept form is given as:

y = mx + c   eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Given equation of line is y = 12x - 2

On comparing the above equation with eqn 1,

m = 12

Thus slope of line is 12

We know that slopes of parallel lines are equal

Therefore, slope of line parallel to given line is also 12

Given point is (-8, 1)

We have to find the equation of line passing through (-8, 1) with slope m = 12

Substitute m = 12 and (x, y) = (-8, 1) in eqn 1

1 = 12(-8) + c

1 = -96 + c

c = 97

Substitute c = 97 and m = 12 in eqn 1

y = 12x + 97

Thus the required equation of line is found

answer:   28.56 feet (approx)

step-by-step explanation:

since, triangle abc has measure of angle c equal to 55 degrees, measure of angle abc equal to 90 degrees, and length of bc equal to 20 feet.

we have to find out the measurement of segment ab.

therefore, tan 55° =

but bc = 20 feet.

⇒ tan 55 ° =  

⇒ ab = 20 × tan 55 °

⇒ ab = 20 × 1.42814800674

⇒ ab = 28.5629601348   ≈ 28.56 feet

the surface area is 124cm²

step-by-step explanation:

length: 4cm

width: 9cm

height:   2cm