Train x is traveling at a constant speed of 30 miles per hour and train y is traveling at a constant speed of 40 miles per hour. if the two trains are traveling in the same direction along the same route but train x is 25 miles ahead of train y, how many hours will it be until train y is 10 miles ahead of train x?

3.5 hours

Step-by-step explanation:

Speed of train X=30 mph

Speed of train Y=40  mph

Relative speed When the two trains travelling in same direction

Relative speed=40-30=10 mph

Total distance =25+10=35 miles

We have to find the time when train Y is 10 miles ahead of train X.

We know that

Time=

Using the formula

Then, we get

Time=

Hence, it will be 3.5 hours until train Y is 10 miles ahead of train X.

3.5 hours.

Step-by-step explanation:

When train Y is at position 0 train  X is at position 25.

Speed = distance / time.

Suppose the distance  travelled by train X  before  Train Y catches up with him is x miles.

Then we have the system

30 = x/ t

40 = (x + 25) / t     where t is the time in hours.

x = 30t  plug this into the second equation

40 = ( 30t + 25) / t

40t  = 30t + 25

10t = 25

t = 2.5 hours.

Now the time taken for  train Y to get 10 miles ahead  is calculated as follows:

Combined speed = 40 - 30 = 10 mph.

so 10 = 10/t

t = 1 hours.

Answer is 3.5 hours.

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( - 4 , -7 )

all the lines must parallel  

step-by-step explanation:

coordinates of c = ( - 1 , 2 )

3 units left = ( -4 , 2 )

9 units down = ( - 4 , 11 )