The isosceles trapezoid is part of an
isosceles triangle with a 46° vertex angle.
enter the measure of an acute base angle of
the trapezoid.

Therefore, the measure of an acute base angle of  the trapezoid are

Step-by-step explanation:

Given:

Consider a Triangle ΔABC,with vertex angle as ∠A,

∠ A = 46°

DECB is an Isosceles trapezoid is part of an  Isosceles triangle,

To Find:

∠ B = ∠C = ?

Solution:

As the Triangle,ΔABC is an Isosceles Triangle

........Base angles are equal

Also we have,

Triangle sum property:

In a Triangle sum of the measures of all the angles of a triangle is 180°.

Therefore, the measure of an acute base angle of  the trapezoid are

5=812a+9+3

step 1: simplify both sides of the equation.

5=812a+9+3

5=(812a)+(9+3)(combine like terms)

5=812a+12

5=812a+12

step 2: flip the equation.

812a+12=5

step 3: subtract 12 from both sides.

812a+12−12=5−12

812a=−7

step 4: divide both sides by 812.

812a /812 = -7/812

a= -1/116

so the answer is

a=   -1/116

c

step-by-step explanation: easy math