Part a) ![A=\frac{3}{4}L^2\ units^2](/tpl/images/0443/0541/6a9fa.png)
Part b) The width of the rectangle is now 37.5% of its length or is now half of 75% of its length.
Step-by-step explanation:
Part a) What is the area of the rectangle?
Let
L ----> the length of rectangle
W ---> the width of the rectangle
Remember that
![75\%=\frac{75}{100}=\frac{3}{4}](/tpl/images/0443/0541/f7339.png)
we know that
The area of rectangle is
----> equation A
we have
-----> equation B
substitute equation B in equation A
![A=L(\frac{3}{4}L)](/tpl/images/0443/0541/d9461.png)
![A=\frac{3}{4}L^2\ units^2](/tpl/images/0443/0541/6a9fa.png)
Part b) The length of the rectangle is doubled. What percent of the length is the width now?
we know that
The length is now 2L (represent the 100%)
The width is 0.75L
using proportion
Find out what percent of the length is the width now
![\frac{2L}{100\%}=\frac{0.75L}{x}\\\\x=0.75L(100)/2L\\\\x=37.5\%](/tpl/images/0443/0541/8f049.png)
therefore
The width of the rectangle is now 37.5% of its length or is now half of 75% of its length.