There are two spinners. the first spinner has three equal sectors labeled 1, 2, and 3. the second spinner has four equal sectors labeled 3, 4, 5, and 6. spinners are spun once.

how many outcomes do not show an odd number on the first spinner and show a 5 on the second spinner?

1

2

3

5

Explanation:

Let's label each pair of outcomes as an ordered pair (x,y)

x = first spinner outcome

y = second spinner outcome

We have these 12 different possible combos

(1,3),   (1,4),   (1,5),   (1,6)

(2,3),  (2,4),  (2,5),  (2,6)

(3,3),  (3,4),   (3,5),  (3,6)

Focus on the third column where y = 5 for each (x,y) pair. Of this column only (2,5) has x be an even number. The other results in that column have x be odd.

Basically (1,5) is the only possible outcome if we want the first spinner to lan on an even number, and the second spinner to land on 5.

step-by-step explanation:

sry but any answer choices

1 + (6 / x - 1)

step-by-step explanation:

divide using polynomial division.