a)) a 55 m long and 35 m broad park is surrounded by a 2.5 m wide
(i) find the area of the path.

Area of the path is 475 m².

Step-by-step explanation:

Let us first draw the diagram for the given question.

Here rectangle ABCD represents a park whose length is 55 m and breadth is 35 m. The shaded portion shows the path all around the park whose width is 2.5 m.

Now, length of rectangle ABCD, l = 55 m

breadth of rectangle ABCD, B = 35 m

Now, width of the path = 2.5 m

So, length of rectangle PQRS, L = 55 + 2.5 + 2.5 = 60 m

breadth of rectangle PQRS, B = 35 + 2.5 + 2.5 = 40 m

Now, to calculate the area of shaded portion or the area of the path, we will subtract the area of the park or area of rectangle ABCD from the area of rectangle PQRS.

Now, area of rectangle PQRS, A₁ = L × B = 60 × 40 = 2400 m²

Area of rectangle ABCD, A₂ = l × b = 55 × 35 = 1925 m²

So, area of the path = A₁ - A₂ = 2400 - 1925 = 475 m²

Hence the area of the path is 475 m².

the ratio of white tiles to blue tiles is 48: 16. the ratio in it's simplest form is 3: 1.

step-by-step explanation:

ratio: take the first number and add a colon next to it, then add the second number after that. make sure the ratio order matches up with the written problem!

simplest form: we can simplify the ratio 48 : 16 by dividing both terms by the greatest common factor (gcf).

the gcf of 48 and 16 is 16.

divide both terms by 16:

48 ÷ 16 = 3

16 ÷ 16 = 1

reducing to simplest form:

48 : 16 = 3 : 1

a

b

d

step-by-step explanation: