Assume that the probability of any newborn baby being a boy is one half and that all births are independent. if a family has three children (no twins), what is the probability of the event that they are all boys?

1/8

Step-by-step explanation:

P(B) = 1/2

Now we are considering that the three children are all boys. This means we are considering that the first is a boy, the second is a boy and the third too is a boy. This brings us to the situation BBB

That is a boy and a boy and another boy. In probability, the word and means we multiply the three.

Hence:

P(BBB) = P(B1) * P(B2) * P(B3) = 1/2 * 1/2 * 1/2 = 1/8 or 0.125

trapezoid

step-by-step explanation:

first i plotted all my points on a grid graph

i made sure all of them were in the correct quadrant

then i saw it was a trapezoid or a quadrilateral