Assume the random variable x is normally distributed, with mean u=50 and standard deviation sd=6. find the 15 th percentile.

44.85.

Step-by-step explanation:

We have been given that the random variable X is normally distributed, with mean u=50 and standard deviation SD=6. We are asked to find the 15th percentile.

We will use normal distribution table to find the z-score corresponding to 15th percentile or 0.15.

Using normal distribution table, we will get z-score of .

Now, we will use z-score formula to find corresponding x-value to z-score of .

, where,

z = Z-score,

x = Sample score,

= Mean,

= Standard deviation.

Upon substituting our given values, we will get:

Therefore, the 15th percentile is 44.85.

answer: 1,380

step-by-step explanation:

1: you turn %15 into a decimal by moving the decimal point two places to the left.

2: and then you multiply .15 by 1,200 , which will get you 180.00

3: from there you will add 180 to 1,200

4: which will get you 1,380

hope it *im kind of slow so idk if my answer is right*