Me solve this identity
(y + x) (ax + b)

ax2+axy+bx+by

Step-by-step explanation:

(y+x)(ax+b)

(y)(ax)+(y)(b)+(x)(ax)+(x)(b)

axy+by+ax^2+bx

ax^2+axy+bx+by

i = 2 / - 5

step-by-step explanation:

evaluation of ( 2 - 4 ) ( p + q ) when p = 2 and q = 5 i, by putting values of p and q,                                                                    

4 candies

step-by-step explanation:

7 x 28 = 196

200 - 196 = 4 candies remaining.