How should this relationship be classified?

Domain = -2, range = -5

Domain =>0, range = 0

domain = 2, range = 5

let y =>f(x)

It can be seen that Function can be linear having common difference 2

F(x) = 2x + 1 for x>0

is satisfied for above values

let's check

F(2) = 2(2)+1 = 4+1 = 5 As given

For x<0 , F(x) = 2x -1

f(-2)= 2(-2) -1= -4-1= -5 As given

For X= 0, F(x)= 2x

So , F(0) = 0 As given

2

step-by-step explanation:

it is rigid.; it is isometric. ; the size is preserved.

step-by-step explanation:

a translation is called an isometry; these are transformations that preserve congruence between pre-images and images.

they are also called rigid transformations, as the only thing that can happen to a pre-image is that it is moved or turned, not stretched or shrunk.

since congruence is preserved, the size is preserved.