Every thursday, matt and dave's video venture has "roll-the-dice" day. a customer may choose to roll two fair dice and rent a second movie for an amount (in cents) equal to the numbers uppermost on the dice, with the larger number first. for example, if the customer rolls a two and a four, a second movie may be rented for $0.42. if a two and a two are rolled, a second movie may be rented for $0.22. let x represent the amount paid for a second movie on roll-the-dice day. the expected value of x is $0.47 and the standard deviation of x is $0.15.if a customer rolls the dice and rents a second movie every thursday for 30 consecutive weeks, what is the approximate probability that the total amount paid for these second movies will exceed $15.00?

a. 0.91

b. 0.09

c. 0.14

d. 0.86

c. 0.14

Step-by-step explanation:

Generally, for a given normal distribution, we can estimate the probability of the normal distribution using the equation below:

P (x greater than ) = pnorm(, mean, sd, lower tail=FALSE)

The following variables are provided in the question:

= 15

n = 30

Therefore:

Mean: E(30*X) = 30(0.47)

Standard deviation: 0.15*

P (y greater than 15) = 1 - pnorm (15, 30*0.47, 0.15*)

P (y greater than 15) = 1 - pnorm (15, 14.1, 0.822) = 0.137

The approximate probability is 0.14

rick has $1400 and sally has $1500

step-by-step explanation:

to find amount of money rick has after 10 years :

principal = $1000 , time = 10 years , rate = 4% annually

to find amount of money sally has after 10 years :

her friend gives to pay her $50 per year, therefore money she has after 10 years = 50 × 10 = $500

also, sally gets $1000 after 10 years,

therefore, total amount of money sally has after 10 years = 500 + 1000 = $1500

so, after 10 years : rick has $1400 and sally has $1500