Convert the following equation to standard form: y = -3x + 2
o3х – у = 2
3х + y = 2
3х + y = -2
—37 — у = 2
ооо

For this case we have that by definition, the equation of a line in its standard form is given by:

We have the following equation in the slope-intersection form:

Where:

-3: It's the slope

2: It is the cut-off point with the y axis.

We manipulate algebraically:

Adding 3x to both sides of the equation we have:

Thus, the correct option is option B.

Option B

answer: 204

step-by-step explanation:

we are told that the revenue is

x⋅(4080−10x)=−10x^2+4080x

this is a quadratic function, so to maximize it we should find the x-value of its vertex. recall that the x-value of the vertex of the parabola ax^2+bx+c is given by the formula −b/2a.

so in this case, we have a=−10 and b=4080, so the x-value of the vertex is

−b/2a= −(4080)/2(−10)=204