Charles wants to determine which car is the fastest. the actual speed of four cars is shown below:

cars a b c d
speed (in km/h) 60.34 60.32 60.33 60.35

if the speedometer can only measure to the nearest tenth of a second, which car will have a different measurement?

Step-by-step explanation:

Given that Charles wants to determine which car is the fastest. The actual speed of four cars is shown below:

Cars                           A                 B          C         D

Speed (in km/h)60.3460.3260.33      60.35

Speed (in m/s)         16.761      16.755    16.758     16.763

Rounded off            16.76        16.76      16.76        16.76

When measured in km/hour, the order from least to greatest is

B, C, A and D

When measured in m/sec, when rounded off to nearest 10th we get

all are having equal speeds.

dc=6 square root of 3 and ac is 12 square root 3

c and d

step-by-step explanation:

square root of 3/2 = 18/c

cross multiply to get 18*2=√3*c

36/√3 * √3/√3 = c

c= 36*√3/3

c=12√3

answer:

c) the x-coordinate of the center of the circle increases by 3