What is the distance between p(-300, 200) and q(500, 400)?

200 √17

Step-by-step explanation:

distance between two points (x,y) and (x',y')

D² = (x' - x)² + (y' - y)²

D² = (500 - (-300))² + (400 - 200)² = 640000 + 40000 = 680000

D = √680000 = √4 x 17 x 10000 = 200 √17

answer: 7270

step-by-step explanation:

answer: domain and range mean all possible values of x and y that could be substituted to the inequality. a solution means all possible values that make the inequality statement true. so while the range is still all real numbers, the solution is the shaded area, for which y will always be greater than the line of the function.