Luiza is jumping on a trampoline. ht models her distance above the ground (in m) t seconds after she starts

jumping. here, t is entered in radians.

h(t) =-0.6 cos (2pi/2.5)t + 1.5

what is the second time when luiza reaches a height of 1.2 m?

round your final answer to the nearest hundredth of a second.

t=2.08 seconds.

Step-by-step explanation:

Well, in this example, H(t)=-0.6cos(2pi/2.5)t+1.5 should be equal to 1.2. If calculated, -0.6cos(0.8pi)t=1.2-1.5 which is equal to -0.6cos(0.8pi)t=-0.3, then cos(0.8pi)t=0.5. The value of cosine in terms of radians when it is equal to 0.5 is pi/3. So, cos(0.8pi)t=cos(pi/3). If simplified, (0.8pi)*t=5pi/3. pi's are cancelled out and t is calculated as 2.08333... If rounded to the nearest hundredth it is 2.08.

2.08 seconds

Step-by-step explanation:

khan academy

i'm sorry i don't know

step-by-step explanation:

x is the total time in minutes for the free response

you are given number of questions as 15 - m and time per item as 8 minutes

to find x multiply the two givens together:

x = 8 * (15-m) = 8(15-m)