Miriam is playing a game of dice. for every 1 or 6 rolled, miriam will in $5. for any other number, she must pay $2. how much money can miriam except to win or lose?

So, she can expect to win a total of $0.33 .

Step-by-step explanation:

According to the question miriam will get 5$ when the dice will show 1 or 6 .

And also she will lose 2$ for any other number .

Now ,

Total number of favorable cases for winning of 5$ for the miriam are 2.

Total number of cases = 6.

Also,

Total number of cases in which she will lose money will be 4.

So, probability of win = .

Probability of loss = .

Thus ,

Total amount of money that she can expect to win =

×5 - ×2 = .

So, she can expect to win a total of $0.33 .

answer

false

explanation

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