Apizza restaurant markets 3 versions of its crazy combo: combo 1 contains
3 cheese pizzas and 1 pepperoni pizza, combo 2 contains 2 cheese pizzas
and 2 pepperoni pizzas, and combo 3 contains 1 cheese pizza and 3
pepperoni pizzas. mr. jenkins orders 5 combo 1s, 2 combo 2s, and 3 combo 3s.

which of the following is a valid conclusion?

a. the probability that mr. jenkins will choose a pepperoni pizza at
random is 11/40.

b. the probability that mr. jenkins will choose a
pepperoni pizza at random is 9/10.

c. the probability that
mr. jenkins will choose a cheese pizza at
random is 9/20.

d. the probability that mr. jenkins will choose a cheese pizza at
random is 11/20.

Step-by-step explanation:

combo 1 : 3 cheese and 1 pepperoni

combo 2: 2 cheese and 2 pepperoni

combo 3: 1 cheese and 3 pepperoni

he chooses :

5 combo 1's : so thats (5 * 3) = 15 cheese, (5 * 1) = 5 pepperoni

2 combo 2's(2*2) = 4 cheese and (2 * 2) = 4 pepperoni

3 combo 3's3(3 * 1) = 3 cheese and (3 * 3) = 9 pepperoni

added = a total of 22 cheese and 18 pepperonithats 40 pizzas

so the probability that he will randomly pick a pepperoni is 18/40 which reduces to 9/20

the probability that he will pick a cheese is 22/40 which reduces to 11/20

so ur answer is D. <===

answer: on graphs, the open and closed circles, or vertical asymptotes drawn as dashed lines us identify discontinuities.

as before, graphs and tables allow us to estimate at best.

when working with formulas, getting zero in the denominator indicates a point of discontinuity.

when working with piecewise-defined functions, check for discontinuities at the transition points where one piece ends and the next begins.

step-by-step explanation:

there still no table