The function f is given by f(x)=1+3cosx. what is the average rate of change of f over the interval [0,π]?

Step-by-step explanation:

To find the average rate of change, we use the formula

Where and

Knowing this, we can plug in all of our know values and simplify.

The average rate of change of f over the interval [0,π] is; -6/π.

According to the question, the function f is given by f(x)=1+3cosx.

In essence, to find the average rate of change of f over the interval, [0,π];

We have to evaluate;

Therefore;

where π = 180°

f(π) = -2.

Also:

Therefore, the average rate of change is given as;

Ultimately, the average rate of change of f over the interval [0,π] is;

-6/π.

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step-by-step explanation:

in the absence of parentheses, i will have to make some assumptions:   i interpret your (3x+5/y^6)(4y^3/5)​ to mean:

3x + 5     4y^(3/5)       (3x + 5)(4)

* =

    y^6             1               y^(6-3/5)

if this is not what you expected, repost your question using parentheses to indicate whether you meant

4y^3

    or   4y^(3/5)

    5