a point p(x, y) is such that its distance form the y-axis is equal to its distance
from the point a(3,2).show that y^2 - 4y - 6x + 13 = 0

Good evening,

Step-by-step

let D represent distance of P form the y-axis

D²=|x|² = x²

AP²=(x-3)²+(y-2)²

D² = AP² ⇌ x² = (x-3)²+(y-2)² ⇌ x² = (x²-6x+9)+(y²-4y+4)

⇌ 0 = -6x+9+y²-4y+4

⇌ y² - 4y - 6x + 13 = 0.

:)

pooopoopopoopop

step-by-step explanati∵∵∴∴on:

the answer is (-8,-5)

step-by-step explanation:

the endpoint to midpoint is half the length. the length is (-2,-1) so when you are at the midpoint just add it to it to find your answer -6+(-2)= -8 and -4+(-1)=-5 so (-8,-5)