Use the drawing tool(s) to form the correct answers on the provided graph.
consider the given function.

h(x)=(x+1)^2-4

plot the x-intercept(s), y-intercept, vertex, and axis of symmetry of the function.

See below in bold.

Step-by-step explanation:

This is the vertex form of a parabola which opens upwards.

To find the x intercept put h(x) = 0:

(x + 1)^2 - 4 = 0

(x + 1)^2 = 4

x + 1 = +/- 2

x = (-3, 0) an (1, 0) are the x-intercepts.

For the y-intercept we put x = 0

y = (0+1)^2 - 4 = -3

y-intercept =  (0, -3).

The vertex  is (-1, -4).

Axis of symmetry is x = -1.

(See attachment below)

Step-by-step explanation:

The following information is derived from the graphic:

X-Intercepts: (-3,0), (1,0)

Y-Intercepts: (0,-3)

Vertex: (-1,-4)

Axis of symmetry of the function: x = -1

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step-by-step explanation:

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im not sure of the names, but the answer is 48