Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random what is the probability that the ticket drawn has a number which is multiple of 3 and 5?

Total number of outcome = 20

Probability of picking multiple of 3 out of 1 - 20 = (6 items of 20) = 6/20

Probability of picking multiple of 5 out of 1 - 20 = (4 items of 20) = 4/20

Therefore p(multiples of 3 or 5) = 6/20 + 4/20 = 10/20 = 1/2.

step-by-step explanation:

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1) c 2143.6 cm

2) c 113.0 m

3) a 33.5 ft

4)   d 2 cm

5) c 20 mm

6) 180 in

7) d 120 ft