Iroll a six-sided die 4 times. find chances for each of the following events: a) the first die roll is bigger than the second or the first roll is a

=0.5278

Step-by-step explanation:

a) The first die roll is bigger than the second or the first roll is a 3

Cases for 2 rolls are   (1,1)(1,2)(1,3)(1,6),(2,1)(2,2) (total 36)

We will get 6 cases when they are equal and 15 when 1st is bigger and 15 when 1st is smaller

So   Let  A is the event when first roll bigger

B is the event when First roll=3

So

P(A)=15/36

P(B) =1/6

P(A and B)=2/36

So

P(A or B)=P(A)+P(B)-P(A and B)

=15/36+1/6-2/36

=19/36

=0.5278

30

step-by-step explanation:

idk

i hope i

y=3x+4

step-by-step explanation:

given the points a(0,4) and b(-4, -8)

eqn of line ab: (y-4)/(x-0)=(-8-4)/(-4-0)

(y-4)/x=-12/-4=3

y=3x+4