Aspring on a horizontal surface can be stretched and held 0.6 m from its equilibrium position with a force of 78 n. a. how much work is done in stretching the spring 5.5 m from its equilibrium position? b. how much work is done in compressing the spring 1.5 m from its equilibrium position?

Step-by-step explanation:

x = 0.6 m

F = 78 N

Let k be the spring constant.

F = k x

78 = 0.6 k

k = 130 N/m

(a)

x = 5.5 m

W = 0.5 kx²

W = 0.5 x 130 x 5.5 x 5.5

W = 7865 J

(B) x = 1.5 m

W = 0.5 kx²

W = 0.5 x 130 x 1.5 x 1.5

W = 146.25 J

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet

70

step-by-step explanation: