Amother is 24 years older than her daughter. before eight years she was seven times her daughter's age. find their present ages

Mother's Present Age = 36 years

Daughter's Present Age = 12 years

Step-by-step explanation:

Let present age of mother be "m" and present age of daughter be "d"

Mother is 24 years older than her daughter, so we can write:

m = 24 + d

8 years ago, Mother was 7 times old as daughter, that would be:

m - 8 = 7(d - 8)

Note, since 8 years ago, both "m" and "d" have 8 subtracted from it.

Now we substitute Equation 1 into Equation 2 and solve for d:

Mother age, m, would be:

m = 24 + d

m = 24 + 12

m = 36

Hence,

Mother's Present Age = 36 years

Daughter's Present Age = 12 years

b. 6

step-by-step explanation:

we are given the table representing an exponential function.

we can see from the table that, as x is increasing, the value of y is increasing in the power of 6.

i.e. the following relation is obtained,

x = 1, y = 6

x = 2, y = 36 =

x = 3, y = 216 =

x = 4, y = 1296 =

x = 5, y = 7776 =

so, the geometric series obtained is .

thus, the common ratio is given by = = 6.

hence, the common ratio is 6.

the answer should be:

a. 3, 4, and 6

b. 18, 24, and 36

c. 4.8, 6.4, and 9.6

hope i

-lavira : )