Mathematics, 24.12.2019 23:31 jay1462
Use the value of the first integral i to evaluate the two given integrals. i = integral^3_0 (x^3 - 4x)dx = 9/4 a. integral^3_0 (8x - 2x^3)dx b. integral^0_3 (4x - x^3)dx c. integral^3_0 (8x - 2x^3)dx =
Answers: 1
Mathematics, 21.06.2019 17:40, skylerdemi1
A. 127 cm^2 b. 144.5 cm^2 c. 172 cm^2 d. 50 cm^2
Answers: 2
Use the value of the first integral i to evaluate the two given integrals. i = integral^3_0 (x^3 - 4...
Mathematics, 27.09.2019 20:20