Mathematics, 24.12.2019 18:31 anayabeatriz

Mirri is traveling in a group of 8 cat warriors. each cat needs 4 liters of milk per day to maintain good morale. mirri has a supply of 96 liters of milk. another cat has enough milk to last for 2 days. which equation can we use to find, d, the total number of days the milk will last?

Answers: 2

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Answer from: 21ltilley

Step-by-step explanation:

Let d represent the total number of days that the milk will last.

The total number of cat warriors travelling together is 8. Each cat needs 4 liters of milk per day to maintain good morale. This means that the 8 cat warriors would need

8 × 4 = 32 liters of milk.

Let n represent the total number of liters of milk available. Therefore, the total number of days the milk will last, d would be

d = n/32

Mirri has a supply of 96 liters of milk. Another cat has enough milk to last for 2 days. This means that the amount of milk that the cat has is 4 × 2 = 8 liters. Total amount of milk available would be

96 + 8 = 104 liters

Therefore

d = 104/32 = 3.25 days

Answer from: Quest

answer: 1722

step-by-step explanation:

given: the mass of saturn= $5.685\times10^{26}\ kgs$

the mass of mercury= $3.302\times10^{23}\ kgs$

the number of times the mass of saturn is greater than the mass of mercury

$=\frac{\text{mass of saturn}}{\text{mass of mercury}}\\=\frac{5.685\times10^{26}}{3.302\times10^{23}}\\\\=1.72168\times10^{26-23}{by using law of exponent}]\\=1.72168\times10^3=1721.68\approx1722$

hence, the mass of saturn is 1722 times greater than the mass of mercury.

Answer from: Quest

step-by-step explanation:

i found the life tables for the year 2012.

life table of males at age 30. probability of dying between ages x and x+1

total population:

29–30 . . . . . . . . . . . . 0.001030

30–31 . . . . . . . . . . . . 0.001061

males:

29–30 . . . . . . . . . . . . 0.001420

30–31 . . . . . . . . . . . . 0.001448

white population

29–30 . . . . . . . . . . . . 0.001005

30–31 . . . . . . . . . . . . 0.001037

white males

29–30 . . . . . . . . . . . . 0.001372

30–31 . . . . . . . . . . . . 0.001399

non hispanic white population

29–30 . . . . . . . . . . . . 0.001083

30–31 . . . . . . . . . . . . 0.001116

non hispanic white males

29–30 . . . . . . . . . . . . 0.001477

30–31 . . . . . . . . . . . . 0.001503

jacob, non hispanic white male. 30 years old.

probability that jacob lives to be 30 years old.

since the given probabilities are probabilities of dying, i think we simply subtract it from 1 to get the probability of living. we will use the probability of non hispanic white male.

probability of living to be 30 y.o.

29 - 30 : 1 - 0.001477 = 0.998523

30 - 31 : 1 - 0.001503 = 0.998497

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Mirri is traveling in a group of 8 cat warriors. each cat needs 4 liters of milk per day to maintain...