H(t)=(t+3)^2+5

over which interval does h have a negative average rate of change?

choose 1

(choice a)

−2≤t≤0

(choice b)

1≤t≤4

(choice c)

−4≤t≤−3

(choice d)

−3≤t≤4

Option C. −4≤t≤−3

Step-by-step explanation:

we have

This is the equation of a vertical parabola written in vertex form

The parabola open upward (the leading coefficient is positive)

The vertex is a minimum

The vertex is the point (-3,5)

The function is increasing in the interval [-3,∞)

The function is decreasing in the interval (-∞,-3]

The function will have a negative average rate when the function will be decreasing

therefore

the answer is option C

sas (side angle side)

aa(angle angle)

sss(side side side)

sas you have to find two sides with an angle in between

aa you find two angles because it will always add up to 180

sss find all sides

step-by-step explanation: