What is an equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 ?

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

Step-by-step explanation:

Given:  

Let,  

point A( x₁ , y₁) ≡ ( -2 , 7)

To Find:  

Equation of Line  that passes through the point (-2,7) and is perpendicular to the line x-6y=42=?  

Solution:  

   ..................Given

which can be written as

Where m is the slope of the line

∴

On Comparing we get

The Required line is Perpendicular to the above line.

So,

Product of slopes = - 1

Slope of the required line is -6

Equation of a line passing through a points A( x₁ , y₁) and having slope m is given by the formula,  

i.e equation in point - slope form

Now on substituting the slope and point A( x₁ , y₁) ≡ ( -2, 7) and slope = -6 we get

The equation of the line that passes through the point (-2,7) and is perpendicular to the line x-6y=42 is

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

the sum of the lengths of any two sides of a triangle is greater than the length of the third side. if you take the three sides of a triangle and add them in pairs, the sum is greater than (not equal to) the third side. if that is not true, then it is not possible to construct a triangle with the given side lengths.

step-by-step explanation: