Solve the problem by using a system of equations.
a motel rents double rooms at $35 per day and single rooms at $23 per day. if 29 rooms were rented one day for
a total of $895, how many rooms of each kind were rented?
single rooms
double rooms

Single Rooms: 10     Double Rooms: 19

Step-by-step explanation:

d=double rooms and s=single rooms. Okay so:

1. Set up your equations. One for the cost of each room and one for the number of rooms. In this case it's 35d+23s=895 and d+s=29

2. You have to get one of the equations to equal one of the variables. For example, in the second equation subtract the s to put it on the other side to get d=29-s

3. Plug in that equation(d=29-s) into the variable d for the first equation: 35(29-s)+23s=895

4. Use the distributive property to get 1,015-35s+23s=895

5. combine like terms to get 1,015-12s=895

6. Subtract the 1,015 over to the other side to get -12s= -120

7. Divide the -120 by the -12 to isolate the s and in return you find that the number of single rooms rented was 10.

8. To find the amount of double rooms plug the 10 into the s for the second equation(d+s=29)

9. subtract the 10 to get the d by itself

10. d=19

answer:   y=2x-3

step-by-step explanation: