Every day going to school, june has to go by boat (point a) over a 217m-wide river to point b (the other bank), and then from b walk to school at point d with distance ad = 170m. in fact, due to the flowing water, the boat was pushed by the water at an angle of 50 degrees and brought her to point c (the other shore). from c, june walk to school. calculate the distance june traveled from a to d. (result rounded to the third decimal place)

Explanation:

The distance traveled by June, from A to D, is the sum of the distance from A to C plus the distance from C to D:

1) Find the distance AC

2) Find the distance DC

First, you need to calculate the side BC which is a common side of both triangles ABC and DBC.

You can use Pythagora's or a trigonometric function (tangent or sine).

Now you can use Pythagora's theorem to find the distance DC, which is the hypotenuse of the triangle DBC:

3) Find the total distance traveled from A to D

check above link.

graphically?   well, you graph them both, the solutions is where they both intersect each other, since there are two solutions, meaning they will meet twice, or namely the linear will run into the quadratic curve twice, and where they meet, those x,y coordinates are the solutions to the system.