Find the average value of the function over the given solid. the average value of a continuous function f(x, y, z) over a solid region q is 1 v q f(x, y, z) dv where v is the volume of the solid region q. f(x, y, z) = x + y + z over the tetrahedron in the first octant with vertices (0, 0, 0), (2, 0, 0), (0, 2, 0) and (0, 0, 2).

Compute the volume of :

Integrate over :

So the average value of over is 2/(4/3) = 3/2.

answer: h=5.6 i don't really know how to put into words, so i though i would let you do that. i hope i was able to some

step-by-step explanation:

18 = 6(h)+1/2

18 = 6h+1/2

18-1 = 6h/2

17 = 3h

17/3 = h

h = 5.6

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convert the exponential equation to a logarithmic equation using the logarithm base (6) of the right side (36) equals the exponent (2).

ℓσg6(36)=2

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