The number of e. coli bacteria cells in a pond of stagnant water can be represented by the function below, where a represents the number of e. coli bacteria cells per 100 ml of water and t represents the time, in years, that has elapsed.

a(t)=136(1.123)^4t

based on the model, by approximately what percent does the number of e. coli bacteria cells increase each year?

a.
60%
b.
59%
c.
41%
d.
40%

Based on the model, percentage of increasing of bacteria in the pond per year is given by, 59% .

Step-by-step explanation:

According to the question,

A(t) = ---------------------(1)

where, A(t) = number of E-coli bacteria cells in the pond per 100 mL of water  at time t year.

So,

A(t+1) =

          --------------------(2)

So, based on the model, percentage of increasing of bacteria in the pond per year is given by,

%

% [from  (1) and (2)]

i believe the answer is d.

hope it you! : d

24

step-by-step explanation: