Which equation goes through the point (-7, 3) and is parallel to y = −8x + 1?

y + 3 = -8(x - 7)

y + 7 = -8(x - 3)

y - 3 = -8(x + 7)

y - 3 = 8(x + 7)

  y - 3 = -8(x + 7)

Step-by-step explanation:

The equation of a line with slope m through point (h, k) is ...

  y -k = m(x -h)

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The slope you want is m = -8, which is the slope of the given line.* The given point is (h, k) = (-7, 3), so the equation you're looking for is ...

  y - 3 = -8(x -(-7))

The expression inside parentheses can be simplified so you have ...

  y - 3 = -8(x + 7)

* The given line is in "slope-intercept" form, which is y = mx + b. Matching this pattern to the given equation, you see that m=-8. Parallel lines have equal slope, so -8 is the slope of the line you're writing the equation for.

x = ± 6i

step-by-step explanation:

x^2 = -36

take the square root of each side

sqrt(x^2) = sqrt(-36)

we know sqrt(ab) = sqrt(a) sqrt(b)

x = ±sqrt(36) sqrt(-1)

we know that sqrt (-1) = i

x = ± 6i

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step-by-step explanation: