Automated manufacturing operations are quite precise but still vary, often with distributions that are close to normal. the width in inches of slots cut by a milling machine follows approximately the n(0.8750, 0.0012) distribution. the specifications allowslot widths between 0.8725 and 0.8775 inch. what proportion of slots meet these specifications?

96.2% of slots meet these specifications.

Step-by-step explanation:

We are given the following information in the question:

Mean, μ = 0.8750

Standard Deviation, σ = 0.0012

We are given that the distribution of width in inches of slots is a bell shaped distribution that is a normal distribution.

Formula:

P( widths between 0.8725 and 0.8775 inch)

96.2% of slots meet these specifications.

on monday rodney ate 1/4th of the sandwich = 3/12

on tuesday he ate 1/3rd of the sandwich = 4/12

therefore in total he has eaten = 3/12 + 4/12 = 7/12

thus we can say that he has eaten 7/12 of the sandwich on monday and tuesday alltogether.

happy to

pls mark as brainliest.