Three times the greatest of three consecutive even integers exceeds twice the least by 38. find the integers

The three numbers are 32,33, and 34.

Step-by-step explanation:

Let the three consecutive integers be for any integer .

Integers are numbers in the set: .

We are given that '3 times greatest of these numbers exceeds 2 times the smallest of these numbers by 38'.

This means as an equation we have:

.

Let's solve the above equation.

Distribute:

Combine like terms on the sides:

Subtract on both sides:

Subtract 3 on both sides:

Now let's find and given that :

So the three numbers are 32,33, and 34.

Let's check.

3(greatest)=3(34)=102

2(least)=2(32)=64

Now let's see if 102 is 38 more than 64.

Since 38+64=102, it is.

in the math equation 8 x 7 = 56, the 8 and the 7 are both factors of 56, since in this lesson we will use square tiles to figure out the factors of a whole find as many different arrays as you can, but follow one important rule: all the rows must have the i can make two rows of nine, so 2 and 9 are both factors of 18.

step-by-step explanation:

option (a)

step-by-step explanation:

step 1:   take 2 number whose product equal to 25..

and sum of those two number are -10

step: 2 for example here if we take 5,5 are the number,,

5*5=25

and

5+5=10

but we need -10

so if we take   -5,-5

so -5*-5=25

and -5+(-5)=-10

s0

come the equation

replace -10x by these number

like -5x -5x+25

take common

x(x-5)-5(x-5)=0

(x-5)(x-5)=0