The position of an object at time t is given by s(t) = 6 - 14t. find the instantaneous velocity at t = 6 by finding the derivative.
by using the difference quotient

It results -14 in either way

Step-by-step explanation:

Velocity As A Rate Of Change

The velocity of an object can be computed as the rate of change of its displacement (or position taken as a vector) over time. If we compute it as a derivative, it's called instantaneous velocity, and if computed as the slope of the function (difference quotient) at a certain point it's the average velocity

The position of the object as a function of time is

Computing the derivative

We can see it's a constant value. If we use the slope or rate of change:

Now let's fix two values for time  

and compute the corresponding positions, by using the given function

Now we compute the average velocity

We get the very same result in both ways to compute v. It happens because the position is related with time as a linear function, it's called a constant velocity motion.

x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

step-by-step explanation:

last month maria hiked the 5-mile mountain trail a number of times and she hiked the 10-mile canal trail several times. let x represent the number of times she hiked the 5-mile trail, and let y represent the number of times she hiked the 10-mile trail. if she hiked a total of 90 miles, which equation can be used to find the number of times maria hiked each trail? x + y = 90 5x – 10y = 90 90 – 10y = 5x 90 + 10y = 5x

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