Increasing numbers of businesses are offering child-care benefits for their workers. however, one union claims that fewer than 80% of firms in the manufacturing sector offer child-care benefits and performs a hypothesis test with a-0.05. a random sample of 390 manufacturing firms is selected and 295 of them offered child-care benefits. symbolically, the null and alternative hypothesis are as follows: hop -0.80 and hap< 0.80 what value of the 2-statistic should he report? round your standard error to four decimal places for calculations.
a. -0.0125
b. 0.0125
c. -2.15
d. 2.15

c. -2.15

Step-by-step explanation:

As per given we have:

Null hypothesis :

Alternative hypothesis :

let p be the proportion of firms in the manufacturing sector offer child-care benefits

A random sample of 390 manufacturing firms is selected and 295 of them offered child-care benefits.

sample size : n= 390

sample proportion :  

Test statistic for proportion :

Substitute the values , we get

Hence, the value of test statistic = -2.15

Correct option is c. -2.15 .

the direct variation says that:

then the equation is of the form is given by:

            where k is the constant variation.

from the given table:

consider any value of x and m(x)=y

x = 2 and m(x)=y = 3

substitute these value in [1]; we have;

divide both sides by 2 we get;

⇒

check:

put x = -1 and m(x) = -1.5

substitute in the equation:

-1.5 = -1.5                   true

therefore, the function m(x) represents a direct variation

graph of this function as shown below:

10 you would take 50/ .2

step-by-step explanation: