Arhombus has side lengths of 25. what could be the lengths of the diagonals?

25√2

For the opposite side, the hypotenuse, a rhombus is always divided by a angle bisector. Therefore you use the 45-45-90 theorem

loloo

step-by-step explanation:

lololool

answer: (-8,4) are the coordinates of a

step-by-step explanation:

let the side of square abcd is x .

thus the area of square abcd is .

now, by the diagram area of triangle ead= 1/2 × ea × ad = 1/2 × ea × x

( because ad is the side of square)

and, according to the question,

the areas of square abcd and right ead are equal.

⇒

⇒ea=2x

thus, ea: ab=2: 1

therefore, point a divides line segment eb into the ratio 2: 1.

⇒ by sectional formula coordinates of a are,

=

=

=(-8, 4)

thus the coordinates of a are (-8,4)