Denzel is coming web sites for downloading music. one charges a 50 membershy lee plus
160.50 per song. another charges & 1.00 per song but has no membership fee. write and solve an equation to find how many songs denzel would have to buy to spend the same amount at both web site

Question is not proper, Proper question is given below.

Denzel is comparing websites for downloading music. One charges a $5 membership fee plus $0.50 per song. Another charges $1.00 per song, but has no membership fee. Write and solve an equation to find how many songs Denzel would have to buy to spend the same amount at both websites.

Denzel would have to buy 10 songs to spend the same amount at both websites.

Step-by-step explanation:

Let the number of songs be 'x'.

Given:

One charges a $5 membership fee plus $0.50 per song.

So the total cost at one site will be membership cost plus charges per song multiplied by number of songs.

framing in equation form we get;

Total Cost at one site =

Another website charges $1.00 per song, but has no membership fee.

So the total cost at Another site will be charges per song multiplied by number of songs.

framing in equation form we get;

Total Cost at Another site =

To find the number of songs that results in same cost we should equate the two expression and solve.

Combining like terms we get;

Now Dividing both side by 0.5 we get;

Hence Denzel would have to buy 10 songs to spend the same amount at both websites.

step-by-step explanation:

(s)he  is right it would be 5.5% because it is smaller than 15.5% or anything smaller than 15.5% in general

the answer   is 200

step-by-step explanation:

this is a problem about poisson probabilities.   i don't know if you've

already studied poisson distributions, or if you have a place to look

to read more about the subject.  

here's how you can see a poisson distribution coming.   when there are

a lot of events that may happen at any time (or any place), and when

you're counting how many of them happen at a particular time (or a

particular place), and each event is independent of the others, then

the result is a poisson distribution.   this is roughly true for the

chocolate chips; one chip being in a cookie has only a small effect on

the probability that another chip will be in the cookie.

once you know you have a poisson distribution, you know a lot.   there

is only one parameter to a poisson distribution, so if you know the

mean, you know everything.   the form of the distribution is

  probability of n chips = {[e^(-x)]*(x^n)} / (n! )