Aretangle has a perimeter (p) of 58 inches. the length (l) is one more than 3 times the width (w)

The rectangle has a perimeter P of 58 inches.The length l is one more than 3 times the width w.write and solve a system of linear equations to find the length and width of the rectangle?

Length(L)=22 inches

Width(W) = 7 inches

Step-by-step explanation:

GIven:-

Perimeter (p)=58 inches,

Length(L)= one more than 3 times the width(W)

Let, W=x   ---------------------------------(equation 1

 -----------------------(equation 2)

Here x is unknown and to find the Width(W) we have to find the value of x.

Now,

Perimeter of rectangle(p) = 2 times length(L) + 2 times width(W)

 ----------------(from equation 1)

  ----------------(given p=58 inches)

         ----------------------(equation 3)

Now substituting the value of equation 3 in equation 2.

as,   -----------------------(from equation 1)

inches -------------------(equation 3)

Therefore, Length(L) = 22 inches and Width(W) = 7 inches.

d) the triangle is a right triangle 60 squared +144 squared= 156 squared

step-by-step explanation:

156 squared is the hypothenuse

so 156= c