Aman jogs at a velocity of 2.5 m/s west for 1,200 s. he then walks at a velocity of 1.0 m/s east for 500 s and then stops to rest. what is the displacement of the man when he stops to rest?

The displacement is 2500 m towards west.

Step-by-step explanation:

Taking west as negative direction and east as positive direction.

Velocity of man jogging west = -2.5 m/s

Time he traveled towards west = 1,200 s

Displacement in west direction =

Velocity of man jogging east = 1.0 m/s

Time he traveled towards east = 500 s

Displacement in west direction =

Total displacement can be calculated by finding the sum of displacement.

Total displacement =

Since, the resultant displacement is negative, so the displacement is 2500 m towards west.

25.2

step-by-step explanation:

2+4x6-8/10= 25.2

x = ±sqrt(10)

step-by-step explanation:

5 - 2x² = -15

subtract 5 from each side

5-5 - 2x² = -15-5

-2x^2   = -20

divide by -2 on each side

-2x^2   /-2= -20/-2

x^2 =10

take the square root on each side

sqrt(x^2 )=±sqrt(10)

x = ±sqrt(10)

check:

5 - 2x² = -15

+sqrt(10)

5 - 2(sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15

-sqrt(10)

5 - 2(-sqrt(10))² = -15

5 -2(10) = -15

5 -20 = -15

-15 = -15