Solve these recurrence relations together with the initial conditions given.

a) an = an−1 + 6an−2 for n ≥ 2, a0 = 3, a1 = 6

b) an = 7an−1 − 10an−2 for n ≥ 2, a0 = 2, a1 = 1

c) an = 6an−1 − 8an−2 for n ≥ 2, a0 = 4, a1 = 10

d) an = 2an−1 − an−2 for n ≥ 2, a0 = 4, a1 = 1

e) an = an−2 for n ≥ 2, a0 = 5, a1 = −1

f ) an = −6an−1 − 9an−2 for n ≥ 2, a0 = 3, a1 = −3

Look at the following graph of the given equation. determine whether the equation is a function. explain why or why not.

Apsychology student wishes to investigate differences in political opinions between business majors and political science majors at her college. she randomly selects 100 students from the 260 business majors and 100 students from the 180 political science majors. does this sampling plan result in a simple random sample? why or why not? no, because each group of 200 students in the sample does not have the same chance of being selected. yes, because each group of 200 students in the sample has the same chance of being selected. no, because each individual student does not have an equal chance of being selected. yes, because each individual student has the same chance of being selected.

2/3(-6y+9x) expand each expression using the distributive property