Fez rolls 2 fair dice and adds the results from each. work out the probability of getting a total of 6

The probability of getting a total of 6 is

Fez rolls 2 fair dice and adds the results from each

To find: probability of getting a total of 6

The probability of an event is given as:

When we roll 2 fair dice, the possible outcomes are

{(1,1) (1,2)(1,3)(1,4)(1,5)(1,6)

(2,1)(2,2)(2,3)(2,4)(2,5)(2,6)

(3,1)(3,2)(3,3)(3,4)(3,5)(3,6)

(4,1)(4,2)(4,3)(4,4)(4,5)(4,6)

(5,1)(5,2)(5,3)(5,4)(5,5)(5,6)

(6,1)(6,2)(6,3)(6,4)(6,5)(6,6) }

So total number of possible outcomes = 36

Favorable outcome is getting a total of 6

(1, 5), (2, 4), (3, 3), (4, 2), (5, 1)

Thus number of favorable outcomes = 5

Probability of getting a total of 6:

Thus the probability of getting a total of 6 is

the equation cos(35) =a/25 can be used to find the length of bc what is the length of bc? round to the nearest tenth

step-by-step explanation:

x =-.20752

step-by-step explanation:

4^(x+2)=12

4^(x+2)=12

take the log base 4 on each side

log 4 (4^(x+2) = log 4(12)

we know log b(a^y) = y log b (a)

(x+2) log 4(4) = log 4 (12)

x+2 = log 4 (12)

we know   logb c = loga c/loga b

we want to convert to base 10   so a = 10

by default, we do not write the 10   c = 4   and b = 10

log4 10 = log 12/log 4

log4 10 = log 12/ log 4

x+2 = log 12/ log 4

subtract 2 from each side

x +2 -2 = log 12/ log 4 -2

x = 1.79248125 -2

x =-.20752