The owner of limp pines resort wanted to know the average age of its clients. a random sample of 25 tourists is taken. it shows a mean age of 46 years with a standard deviation of 5 years. the margin of error of a 98 percent ci for the true mean client age is approximately:

Step-by-step explanation:

Since we have given that

Sample size = 25

Mean = 46 years

Standard deviation = 5 years

We need to find the margin of error of a 98% confidence interval for the true mean client age.

So, Margin of error is given by

Hence, margin of error is 2.33.

step-by-step explanation:

20% of 120 is 24. if you subtract 24 from 120 you get 96

46 dollars is the answer.

step-by-step explanation:

6*6 = 36,         36+10=46