We consider buying three kinds of food. food i has 1 unit of vitamin a, 3 units of vitamin b, and 4 units of vitamin c. food ii has 2, 3, and 5 units, respectively and food iii has 3, 0 and 3 units, respectively. we need to have 11 units of vitamins a, 9 of vitamin b, and 20 of vitamin c. (a) find all possible amounts of three foods that will provide precisely these amounts of vitamins. (b) if food i costs 60 cents and the others cost 10 cents each per unit, is there a solution costing exactly 100 cents.

1\dotplus 2\times 2\dotplus 3\times 2

Step-by-step explanation:

we will take 1 times unit of A from food 1 and 2 times of unit of A from second food and 2 times unit from third

similarly for B we take 1times unit from food 1 and 2times unit from second and 2 times of unit from third

then we get desired A=11,B=9,C=20

hello from mrbilldoesmath!

answer:

25x^2 + 90x + 84

discussion:

mn(x) = m(n(x)) = m( 5x + 9) =

(5x + 9)^2 + 3 =>

25x^2 + 90x + 9^2 + 3 =

25x^2 + 90x + 84                 (as 9^2 = 9*9 = 81)

which is the second choice

regards,  

mrb

p.s.   i'll be on vacation from friday, dec 22 to jan 2, 2019. have a great new year!

answer: the answer is e

step-by-step explanation: