Products of polynomials
find the product,.
(4a-ts)(2a+2ts)

(4a + 2)3

Step-by-step explanation:

(4a + 2)(4a + 2)(4a + 2)           multliply first two with FOIL

(16a2 +16a + 4)(4a + 2)           multiply these using distributive

16a2(4a) + 16a(4a) + 4(4a) + 16a2(2) + 16a(2) + 4(2)

64a3 + 64a2 + 16a + 32a2 + 32a + 8

64a3 + 96a2 + 48a + 8

plz yuo

step-by-step explanation:

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.